Design Column

07/01/2011

(jumaat)

10 pagi - 12.30 tghari

subuh ku bangun,niat hati nak siapkan latihan yg nk dihantar kt en.shamsul mase klas pagi ni.

pas solat,kebisaan ye aku akn tdo.tp kerna semlm ngatuk sgt,aku x sempt nk salin lik cun2.

so pagi ni la aku wat pai la siap, lam kul9.30 baru ku mandi *almaklum kelas kul10

ok setel.time go to class now...waaaaaaa..ujan pulak,mujur skunt ni tumpang kete kak.ieka je.heheh

ok,menunggu soklan column pulak arini,

agak simple je,just kene ingt r cmne nk wat

step boleh r wat *sebb dy kasi satu force je

hermmm....kan baguh klu cmni beljaq dulu,kni aku bru betol faham.

okaylah,ni step tuk design column,

*get a member buckling resistance :

1) find ecentricity

ex (mm) = D/2 + 100

Mx (kNm)= Rxex

2) classification :

axial compression

py=275 (stndart grade)

Flange ,T & b/T (mm)

web ,t & d/t (210 exponent/1+2r2) > 40 exponent

r2 (kN)= (fc x 10^3 / Ag py) - dlm bs ade

gune section 1,2,3,or 4 slender

ok!!

3) slenderness (lamda)

LE : kL (m/s 80) - ikut type pe dy nk

lamda x : LE/rx

lamda y : LE/ry

refer table 23

(find section I =tak same size & H=same size)

refer table 24 (interpolite - N/mm^2)

Pcx = amik palg kecil (m.s 80)

section 1,2,3 : Pc = Ag x Pcx (kN)

section 4 slender : Pc =Aeff Pcx (m/s 40)

4) member buckling resistance

Fc/Pc + mxMx/PyZx(10^-3) + myMy/PyZy <>

(mx = o.6)

ok!!

hehehe...simple step kan...kene jage2 gan unit la...

insyaallah leh ingat....

okay.doakn shikin dan kawan-kawan berjya menjawab...

daaa~~